Volume 2011, Article ID 158060,8pages doi:10.1155/2011/158060
Research Article
Oscillation and Asymptotic Behaviour of
a Higher-Order Nonlinear Neutral-Type Functional
Differential Equation with Oscillating Coefficients
Mustafa Kemal Yildiz,
1Emrah Karaman,
2and H ¨ulya Durur
31Department of Mathematics, Faculty of Science and Arts, Afyon Kocatepe University, ANS Campus, 03200 Afyon, Turkey
2Department of Mathematics, Faculty of Science and Arts, Karab ¨uk University, 78050 Karab ¨uk, Turkey 3Department of Technical Programs, Vocational High School of Ardahan, Ardahan University,
75000 Ardahan, Turkey
Correspondence should be addressed to Mustafa Kemal Yildiz,myildiz@aku.edu.tr
Received 6 August 2010; Accepted 16 April 2011 Academic Editor: J. C. Butcher
Copyrightq 2011 Mustafa Kemal Yildiz et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
We will study oscillation of bounded solutions of higher-order nonlinear neutral delay differential equations of the following type:yt ptfyτtn qthyσt 0, t ≥ t0, t ∈R, where
p ∈ Ct0, ∞,R, limt → ∞pt 0, q ∈ Ct0, ∞,R, τt, σt ∈ Ct0, ∞,R, τt, σt < t, limt → ∞τt, σt ∞, and f, h ∈ CR, R. We obtain sufficient conditions for the oscillation of all
solutions of this equation.
1. Introduction
In this paper, we are concerned with the oscillation of the solutions of a certain more general higher-order nonlinear neutral-type functional differential equation with an oscillating coefficient of the form
yt ptfyτtn qthyσt 0, t ≥ t0, t ∈ R, 1.1
where p ∈ Ct0, ∞, R is oscillatory and limt → ∞pt 0, q ∈ Ct0, ∞, R, τt, σt ∈
Ct0, ∞, R, τt, σt < t, limt → ∞τt ∞, limt → ∞σt ∞, and f, h ∈ CR, R. As it is
customary, a solution yt is said to be oscillatory if yt is not eventually positive or not eventually negative. Otherwise, the solution is called nonoscillatory. A differential equation
is called oscillatory if all of its solutions oscillate. Otherwise, it is nonoscillatory. In this paper, we restrict our attention to real-valued solutions y.
In1,2, several authors have investigated the linear delay differential equation
xt qtxσt 0, t ≥ t0, 1.2
where q ∈ Ct0, ∞, R and σt ∈ Ct0, ∞, R. A classical result is that every solution of
1.2 oscillates if lim inf t → ∞ t σt qsds > 1 e. 1.3
In 3, Zein and Abu-Kaff have investigated the higher-order nonlinear delay
differential equation
xt ptxτtn ft, xt, xσt st, t ≥ t0, t ∈ R, 1.4
where p ∈ Ct0, ∞, R, limt → ∞pt 0, τt, σt ∈ Ct0, ∞, R, τt, σt < t, limt → ∞τt
∞, limt → ∞σt ∞, f : R× R × R → R is continuous, yft, x, y > 0 for xy > 0, there exists
an oscillatory function r ∈ CnR
, R, such that rnt st, limt → ∞rt 0.
In 4, Bolat and Akin have investigated the higher-order nonlinear differential
equation yt ptyτtn m i1 qitfi yσit st, 1.5
where pt, qit, τt, st ∈ Ct0, ∞, R for i 1, . . . , m, pt and st are oscillating
functions, qit ≥ 0 for i 1, . . . , m, σit ∈ C1t0, ∞, R, σit > 0, σit ≤ t, limt → ∞σit ∞
for i 1, . . . , m, limt → ∞τt ∞, fiu ∈ CR, R is nondecreasing function, ufu > 0 for
u / 0, and i 1, . . . , m. If n is odd, limt → ∞pt 0, limt → ∞rt 0, and
∞
t0 νn−1qνdν ∞
for i 1, . . . , m, then every bounded solution of 1.5 is either oscillatory or tends to zero
as t → ∞. If n is even, limt → ∞pt 0, and limt → ∞rt 0, there exists a continuously
differentiable function ϕt lim sup t → ∞ t t0 ϕν m i1 qiνdν ∞, lim sup t → ∞ t t0 ϕν2 ϕνσiνσin−2ν dν < ∞, 1.6
then every bounded solution of1.5 is either oscillatory or tends to zero as t → ∞.
Recently, many studies have been made on the oscillatory and asymptotic behaviour of solutions of higher-order neutral-type functional differential equations. Most of the known results which were studied are the cases when fu Iu, where I is the identity function; see, for example,1–15 and references cited there in.
The purpose of this paper is to study oscillatory behaviour of solutions of1.1. For
the general theory of differential equations, one can refer to 5,6,12–14. Many references to
some applications of the differential equations can be found in 2.
In this paper, the function zt is defined by
zt yt ptfyτt. 1.7
2. Some Auxiliary Lemmas
Lemma 2.1 see 5. Let y be a positive and n-times differentiable function on t0, ∞. If ynt
is of constant sign and not identically zero in any intervalb, ∞, then there exist a t1 ≥ t0and an
integer l, 0 ≤ l ≤ n such that nl is even, if ynt is nonnegative, or nl odd, if ynt is nonpositive, and that, as t ≥ t1, if l > 0, ynt > 0 for k 0, 1, 2, . . . , l − 1, and if l ≤ n − 1, −1k1ynt > 0 for
k l, l 1, . . . , n − 1.
Lemma 2.2 see 5. Let yt be as in Lemma 2.1. In addition limt → ∞yt / 0 and
yn−1tynt ≤ 0 for every t ≥ ty; then for every λ, 0 < λ < 1, the following hold:
yt ≥ λ
n − 1!tn−1yn−1t for all large t. 2.1
3. Main Results
Theorem 3.1. Assume that n is even,
C1 there exists a function H : R → R such that H is continuous and nondecreasing and
satisfies the inequality
−H−uv ≥ Huv ≥ KHuHv, for u, v > 0, 3.1
where K is a positive constant, and
|hu| ≥ |Hu|, Hu
u ≥ γ > 0, Hu > 0, for u / 0, 3.2
C2 limt → ∞pt 0,
C3
∞
t0 sn−1qsds ∞
and every solution of the first-order delay differential equation wt qtKγH 1 2 λ n − 1!σn−1t wσt 0 3.3
Proof. Assume that1.1 has a bounded nonoscillatory solution y. Without loss of generality,
assume that y is eventually positive the proof is similar when y is eventually negative. That is, yt > 0, yτt > 0, and yσt > 0 for t ≥ t1 ≥ t0. Further, suppose that y does not tend
to zero as t → ∞. By 1.1 and 1.7, we have
znt −qthyσt≤ 0, t ≥ t1. 3.4
It follows that zαtα 0, 1, 2, . . . , n − 1 is strictly monotone and eventually of constant sign. Since y is bounded and does not tend to zero as t → ∞, by virtue of C2,
limt → ∞ptfyτt 0. Then we can find a t2≥ t1such that zt yt ptfyτt > 0
eventually and zt is also bounded for sufficiently large t ≥ t2. Because n is even and n l
odd for znt ≤ 0 and zt > 0 is bounded, byLemma 2.1, since l 1 otherwise, zt is not bounded, there exists a t3≥ t2such that for t ≥ t3
−1k1zkt > 0 k 1, 2, . . . , n − 1. 3.5
In particular, since zt > 0 for t ≥ t3, z is increasing. Since y is bounded,
limt → ∞ptfyτt 0 by C2. Then, there exists a t4 ≥ t3by1.7,
yt zt − ptfyτt≥ 1
2zt > 0, 3.6
for t ≥ t4. We may find a t5≥ t4such that for t ≥ t5, we have
yσt ≥ 1
2zσt > 0. 3.7
From3.4 and 3.7, we can obtain the result of
znt qth 1 2zσt ≤ 0, 3.8
for t ≥ t5. Since z is defined for t ≥ t2, and zt > 0 with znt ≤ 0 for t ≥ t2and not identically
zero, applying directlyLemma 2.2second part, since z is positive and increasing, it follows
fromLemma 2.2that
yσt ≥ 1
2
λ
UsingC1 and 3.7, we find for t ≥ t6≥ t5, hyσt≥ Hyσt ≥ H 1 2 λ n − 1!σn−1tzn−1σt ≥ KH 1 2 λ n − 1!σn−1t H zn−1σt ≥ KγH 1 2 λ n − 1!σn−1t zn−1σt. 3.10
It follows from3.4 and the above inequality that zn−1t is an eventually positive solution
of wt qtKγH 1 2 λ n − 1!σn−1t wσt ≤ 0. 3.11
By a well-known resultsee 14, Theorem 3.1, the differential equation
wt qtKγH 1 2 λ n − 1!σn−1t wσt 0, t ≥ t7≥ t6 3.12
has an eventually positive solution. This contradicts the fact that1.1 is oscillatory, and the
proof is completed.
Thus, fromTheorem 3.1and 11, Theorem 2.3 see also 11, Example 3.1, we can
obtain the following corollary.
Corollary 3.2. If lim inf t → ∞ t σtqsH 1 2 λ n − 1!σtn−1 ds > 1 eKγ, 3.13
then every bounded solution of1.1 is either oscillatory or tends to zero as t → ∞.
Theorem 3.3. Assume that n is odd and (C2), (C3) hold. Then, every bounded solution of1.1 either
oscillates or tends to zero as t → ∞.
Proof. Assume that1.1 has a bounded nonoscillatory solution y. Without loss of generality,
assume that y is eventually positive the proof is similar when y is eventually negative. That is, yt > 0, yτt > 0, and yσt > 0 for t ≥ t1 ≥ t0. Further, we assume that yt does not
tend to zero as t → ∞. By 1.1 and 1.7, we have for t ≥ t1
znt −qthyσt≤ 0. 3.14
That is, znt ≤ 0. It follows that zαt α 0, 1, 2, . . . , n − 1 is strictly monotone and eventually of constant sign. Since limt → ∞pt 0, there exists a t2 ≥ t1, such that for t ≥ t2,
we have zt > 0. Since y is bounded, by virtue of C2 and 1.7, there is a t3 ≥ t2 such
that z is also bounded, for t ≥ t3. Because n is odd and z is bounded, byLemma 2.1, since
l 0 otherwise, zt is not bounded, there exists t4 ≥ t3, such that for t ≥ t4, we have
−1kzkt > 0 k 1, 2, . . . , n − 1. In particular, since zt < 0 for t ≥ t
4, z is decreasing.
Since z is bounded, we may write limt → ∞zt L, −∞ < L < ∞. Assume that 0 ≤ L < ∞.
Let L > 0. Then, there exist a constant c > 0 and a t5 with t5 ≥ t4, such that zt > c > 0 for
t ≥ t5. Since y is bounded, limt → ∞ptfyτt 0 by C1. Therefore, there exists a constant
c1 > 0 and a t6 with t6 ≥ t5, such that yt zt − ptfyτt > c1 > 0 for t ≥ t6. So, we
may find t7with t7≥ t6, such that yσt > c1> 0 for t ≥ t7. From3.14, we have
znt ≤ −qthc1 t ≥ t7. 3.15
If we multiply3.15 by tn−1and integrate from t
7to t, then we obtain Ft − Ft7 ≤ −hc1 t t7 qssn−1ds, 3.16 where Ft t γ2 −1γ tn−1zn−γ−1t γdt. 3.17
Since−1kzkt > 0, for k 1, 2, . . . , n − 1 and t ≥ t4, we have Ft > 0 for t ≥ t7. From3.16,
we have −Ft7 ≤ −hc1 t t7 qssn−1ds. 3.18 ByC3, we obtain −Ft7 ≤ −hc1 t t7 qssn−1ds −∞, 3.19
as t → ∞. This is a contradiction. So, L > 0 is impossible. Therefore, L 0 is the only possible case. That is, limt → ∞zt 0. Since y is bounded, by virtue of C2 and 1.7, we obtain
lim
t → ∞yt limt → ∞zt − limt → ∞ptf
yτt 0. 3.20
Now, let us consider the case of yt < 0 for t ≥ t1. By1.1 and 1.7,
znt −qthyσt≥ 0 t ≥ t1. 3.21
That is, znt ≥ 0. It follow that zαt α 0, 1, 2, . . . , n − 1 is strictly monotone and eventually of constant sign. Since limt → ∞pt 0, there exists a t2 ≥ t1, such that for t ≥ t2,
we have zt < 0. Since yt is bounded, by virtue of C2 and 1.7, there is a t3≥ t2such that
zt is also bounded, for t ≥ t3. Assume that xt −zt. Then, xnt −znt. Therefore,
xt > 0 and xnt ≤ 0 for t ≥ t3. From this, we observe that xt is bounded. Because n is
odd and x is bounded, byLemma 2.1, since l 0 otherwise, x is not bounded, there exists a t4 ≥ t3, such that−1kxkt > 0 for k 1, 2, . . . , n − 1 and t ≥ t4. That is,−1kzkt < 0
for k 1, 2, . . . , n − 1 and t ≥ t4. In particular, for t ≥ t4, we have zt > 0. Therefore, zt
is increasing. So, we can assume that limt → ∞zt L, −∞ < L ≤ 0. As in the proof of
yt > 0, we may prove that L 0. As for the rest, it is similar to the case yt > 0. That is,
limt → ∞yt 0. This contradicts our assumption. Hence, the proof is completed.
Example 3.4. We consider difference equation of the form
yt 1 tsint y3t − 2 yt − 2 4 1 t2y 3t − 3 0, 3.22
where n 4, τt t−2, pt 1/t sint, qt 1/t2, σt t−3, hy y3, and fy y3y.
By taking Hu u, lim inf t → ∞ t t−3 1 s2 1 2 1 3! s − 3 23 3 ds > 1 e, 3.23
we check that all the conditions ofTheorem 3.1are satisfied and that every bounded solution of3.22 oscillates or tends to zero at infinity.
Example 3.5. We consider difference equation of the form
yt cos te−5t2y5t − 5 2yt − 53 t2y2t − 3 0, t ≥ 2, 3.24
where n 3, qt t2, σt t − 3, τt t − 5, and pt cos te−5t2
, fy y5− 2y, hy y2.
Hence, we have lim t → ∞pt limt → ∞ 1 e5t2cos t 0, ∞ t0 sn−1qsds ∞ t0 s4ds ∞. 3.25
Since ConditionsC2 and C3 ofTheorem 3.3are satisfied, every bounded solution of3.24
oscillates or tends to zero at infinity.
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