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Başlık: Calculation method for quadratic programming problem in Hilbert spaces, partially ordered by cone with empty interiorYazar(lar):AHMETOĞLU, FeyzullahCilt: 62 Sayı: 2 Sayfa: 011-015 DOI: 10.1501/Commua1_0000000694 Yayın Tarihi: 2013 PDF

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CALCULATION METHOD FOR QUADRATIC PROGRAMMING PROBLEM IN HILBERT SPACES, PARTIALLY ORDERED BY

CONE WITH EMPTY INTERIOR

FEYZULLAH AHMETO ¼GLU

Abstract. In the article, a numerical method for convex programming prob-lem (with linear inequality) in Hilbert spaces is given. Firstly, by Khun-Tucker conditions problem is reduced to minimize a convex funtional under nonnega-tive variables. Then, last problem is solved by coordinate descent method.

1. Introduction

Various quadratic programming problems in …nite dimensional spaces have been solved by using of simplex method. Unfortunately there is no an analog of sim-plex method in in…nite dimensional spaces and naturally the solution of quadratic programming problems in in…nite dimensional spaces requires di¤erent approaches. During of the last years many papers are devoted to the solution of quadratic programming problems in in…nite dimensional spaces [2]-[5].

In this paper we present a method of solution for quadratic programming prob-lems in Hilbert spaces partially ordered by a cone with empty interior. By using Kuhn-Tucker condition the problem is reduced to simplier problem solvable by known methods.

2. Formulation of the problem.

Let Cij and Aij be linear bounded operator from Hilbert space H into itself.

The space H is partially ordered by convex closed cone K. Consider the following quadratic programming problem:

Received by the editors May 21, 2013; Accepted: July 02, 2013. 2000 Mathematics Subject Classi…cation. 90C20, 65K05.

Key words and phrases. Convex function, Khun-Tucker conditions, minimization method.

c 2 0 1 3 A n ka ra U n ive rsity

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n X i=1 n X j=1 (xi; Cijxj) + n X j=1 (pi; xj) ! min n X j=1 Aijxj bi; i = 1; : : : ; m where bi2 H; pi2 H.

The problem can be reformulated as

(x; Cx) + (p; x) !: min (2.1)

Ax b (2.2)

where C = [cij] is a n n matrix and A = [aij] is a m n matrix.

Suppose that the matrix C is self-conjugated and positively determined: there is a positive number such that for any x 2 Hn

(x; Cx) jjxjj2

De…nition. The restriction (2:2) is said to be strongly simultaneous, if there is a real number 0 > 0 such that for all b from the set M = fb 2 Hm : jjb bjj 0g

the condition Ax b is consistent.

3. The description of the method.

Suppose that the restriction (2:2) is strongly simultaneous and for each i; 1 i m there is ji such that the operator Aiji satis…es the following condition:

there is iji > 0 such that for any x 2 H jjAijijj ijijjxjj

Since the strongly simultaneity condition is satis…ed we can derive Kuhn-Tucker conditions [1] for the problem (2:1); (2:2):

2Cx + p + A w = 0 (3.1)

Ax + y = 0 (3.2)

(y; u) = 0 (3.3)

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From (3:1) we get

x = 1

2C

1(A u + p) (3.5)

By inserting x from(3:5) into (3:2) we get the following Kuhn-Tucker conditions:

2Gu + h y = 0 (3.6)

(y; u) = 0 (3.7)

y 0; u 0 (3.8)

where G = 14AC 1A ; h = 1

2AC 1p + b.

Clearly G is a nonnegative operator: for any z 2 Hm we have (z; Gz) 0:

Di-agonal element of matrix G are positively determined operators, but the operator G need not to be positively determined operator. Indeed,

gii= (Ai1; : : : ; Ain)C 1 0 B @ Ai1 .. . Ain 1 C A Let us denote 0 B @ Ai1 .. . Ain 1 C A by Ai. Then (ui; giiui) = (Aiui; C 1Aiui) 1jjAiuijj2 = 1( n X j=1 jjAiuijj)2 1jjAijiuijj 2 ijijjuijj 2

Conditions (3:6) (3:8) are Kuhn-Tucker conditions for the problem

(u) = (u; Gu) + (h; u) ! min (3.9)

u 0 (3.10)

For the solution of (3:9),(3:10) problem we propose the following method of non-coordinate descent. We choose an initial u(0) 0. Components of n th iteration

are determined by minimization of (u) with respect to ui at ui 0.The other

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(uk+1) (uk); k = 1; 2; : : : (3.11) Theorem 3.1. The sequence fukg converges to the solution of the problem (3:9),(3:10).

Proof. Let uk+1= P u(k). It can be easily shown that the operator P is continuous. Due to (3:11)

(P u) (u)

Let us show that (P u) = (u) if and only if u = ~u, where ~u is a solution of (3:9),(3:10). The necessity of this condition is obvious. Let us prove the su¢ ciency. From (P ~u) = (~u) it follows that for all i = 1; : : : ; m

minui 0: ( ~u1; : : : ; ~ui 1; ui; : : : ; ~um) = ( ~u1; : : : ; ~um) Now @ ( ~u1; : : : ; ~um) @ui 0; : i = 1; : : : ; m (3.12) (@ ( ~u1; : : : ; ~um) @ui ; ui) = 0; : i = 1; : : : ; m (3.13)

The conditions(3:12), (3:13) are Kuhn-Tucker conditions of the problem (3:9),(3:10). Thus, u is a solution of the problem (3:9),(3:10).

Proof. The sequence fu(k)g is a subsequence of the sequence fqpg, where q0= u(0)

and qp is a one coordinate descent of q(p 1). Since (u) is a strongly convex

functional of ui, the following inequality is held:

jjqp q(p 1)jj2 2( (qp 1) (qp)); : p = 1; : : : (3.14)

where 0 < < : min1 i m : f iyig. The sequence (q

(p)) converges as a

monotonically decreasing and bounded from below sequence. From (3:14) it follows that the sequence q(p) also converges. The sequence fu(k)g as a subsequence of convergent sequence fq(p)g also converges. Let u be a limit of the sequence fu(k)g.

Let us show that u is a solution of the problem(3:9),(3:10).

The continuity of (u) implies that (u(k)) ! (u( )). Now (u(k+1)) = (P u(k)) ! (P u( )). Since the limit is unique we get (u( )) = (P u( )).

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As it was mentioned above, in order to …nd components of each iteration one have to minimize (u) with respect to ui. For this purpose one of the known methods

can be applied (for example the method of gradient projection).

References

[1] [1] F.Ahmetoglu, Kuhn-Tucker conditions for a convex programming problem in Banach spaces partially ordered by cone with empty interior. Numerical Functional Analysis and Optimization, v. 33, 4, pp. 363-373, 2011.

[2] [2] S.Y.Chen, S.Y.Wu, Algorithms for in…nite quadratic programming in Lp spaces. Journal of Computational and Applied Mathematics, v. 213, 2, pp. 408-422, 2008.

[3] [3] S.Y. Wu, A cutting plane approach for solving quadratic in…nite programming on measure spaces. Journal of Global Optimization, v. 21, 1, pp. 67-87, 2001.

[4] [4] J. Semple, In…nite positive-defnite quadratic programming in a Hilbert space. Journal of Optimization Theory and Applications, v. 88, 3, pp. 743-749, 1996

[5] [5] S.C. Fang, C.J. Lin, S. Y. Wu, Solving quadratic semiin…nite programming problemsby using relaxed cutting-plane scheme. Journal of Computational and Applied Mathematics, v. 129, pp. 89-104, 2001.

Current address : Faculty of Education, Giresun University, Giresun, TURKEY E-mail address : feyzullah.ahmetoglu@giresun.edu.tr

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