• Sonuç bulunamadı

Checking a practical discrete-time asymptotic stability for an interval matrix

N/A
N/A
Protected

Academic year: 2021

Share "Checking a practical discrete-time asymptotic stability for an interval matrix"

Copied!
6
0
0

Yükleniyor.... (view fulltext now)

Tam metin

(1)

Applied Mathematics

Checking a practical discrete-time asymptotic

stability of an interval matrix

Ayse Bulgak

Research Center of Applied Mathematics, Selcuk University, Konya, Turkey e-mail:abulgak@selcuk.edu.tr

Received: April 21, 2001

Summary.

In this paper we investigate an algorithm for checking a practical discrete-time asymptotic stability of an interval matrix.

Key words:

an interval matrix, discrete-time asymptotic stability, quality of asymptotic stability

Mathematics Subject Classication (1991): 65F30, 65G10, 15A18

1. Introduction

A matrix A is said to be discrete-time asymptotically stable if the Lyapunov matrix equation A HA;A+I = 0 with the identical matrix I has a unique positive de nite solution H = H  H > 0. Moreover, if A is discrete-time asymptotically stable then the value

!(A) = jjHjj

1 is known as the quality of stability for A 1],2]. For non-discrete-time asymptoticallystableAwe assume that!(A) =1. The parameter !(A) is a continuous function with respect to the entries of A. If !(A) < ! then A is known as a practical discrete-time asymptotically stable (! -stable) matrix. In 2] it was shown that the following theorem is true.

Theorem 1.

LetA be an discrete-time asymptotically stable matrix. Then for an arbitrary matrix B such that

jjBjj 1 20!3=2(A) 1 Here and everywhere in the sequel we use the notation

jjjjto designate the

(2)

the sum A+B is also an discrete-time asymptotically stable matrix and j!(A+B);!(A)j5! 5=2(A) jjBjj 0:75!(A)!(A+B)1:25!(A):

The algorithm which we suggest here is a generalization of the algorithm 3] for discrete-time asymptotic stable interval matrices.

2. Quality of discrete-time asymptotic stability of an

interval matrix

Let

A

=f

A

ij

g be a N-dimensional square interval matrix and the entries

A

ij = a

ija

ij] ofAare the intervals of the real line. The real number

!(

A

) = sup A2A

f!(A)g

is known as the quality of stability of the interval matrix

A

. It is clear that for an orthogonal matrixQ we have

!(

A

) =!(Q

A

Q):

3. Practical discrete-time asymptotically stable and

practical non-discrete-time asymptotically stable interval

matrices

Let

A

=f

A

ij

gbe aN-dimensional square interval matrix and let! be a real number! >1. If!(

A

)< ! then

A

is said to be practical discrete-time asymptotically stable (! -stable). Otherwise,

A

is said to be practical non-discrete-time asymptoticallystable (! -unstable).

4. Algorithm for a matrix with only one interval entry

Let! be a real number! >1 and

A

= 8 > > > < > > > : a11b11] a12 ::: a1N a21 a22 ::: a2N ... ... ... ... aN1 aN2::: aNN 9 > > > = > > > 

be an interval matrix with only one interval entry in position (1,1). Our aim is to nd the nite sequence of matrices. Analysis of matrices

(3)

from the sequence allows us to guarantee that the initial interval ma-trix

A

is practical discrete-time asymptotically stable or not practical discrete-time asymptotically stable.

Let A= 8 > > > < > > > : a11 a12 ::: a1N a21 a22 ::: a2N ... ... ... ... aN1 aN2 ::: aNN 9 > > > = > > >  : Then

A

= A+ 0b11 ;a 11] E

11. Here Epq is a real matrix the element of Epq in position (pq) equals 1 and all other elements of

Epq are equal to 0.

The algorithm is as follows

1.

We assume thatA0=A.

1.1.

We compute the maximal singular value N(A0) ofA0.

1.2.

IfN(A0)> !

1=2 then the process stops with the answer\the

given interval matrix

A

is not practical discrete-time asymp-totically stable",!(

A

)> ! .

1.3.

We compute h1= 1 20!3=2(A 0) and check the inequalitya11+h1

b

11:If the inequality holds then the process stops with the answer

!(

A

)<1:25!(A0): Otherwise, we go to Step 2.

2.

We assume thatA1=A0+h1 E

11.

2.1.

We compute the maximal singular value N(A1) ofA1.

2.2.

IfN(A1)> !

1=2 then the process stops with the answer\the

given interval matrix

A

is not practical discrete-time asymp-totically stable",!(

A

)> ! .

2.3.

We compute h2= 1 20!3=2(A 1) and check the inequalitya11+h1+h2

b

11:If the inequality holds then the process stops with the answer

!(

A

)<1:25 max j=01

!(Aj): Otherwise, we go to Step 3.

(4)

After (k;1) steps of the process a matrixA

k ;2 and a real number

hk ;1 are computed.

k.

We assume that Ak ;1=Ak ;2+hk ;1 E

11.

k.1.

We compute the maximal singular value N(Ak ;1) ofAk ;1.

k.2.

If N(Ak ;1) > !

1=2 then the process stops with the an-swer\the given interval matrix

A

is not practical discrete-time asymptotically stable",!(

A

)> ! .

k.3.

We compute hk = 1 20!3=2(A k ;1)

and check the inequalitya11+h1+h2+:::+hk b

11:If the inequality holds then the process stops with the answer

!(

A

)<1:25 max j=01:::k ;1 !(Aj): Otherwise, we go to Stepk+ 1. Since hj  1=(20!

3=2) it follows that the algorithm will stop after not more thenM11 steps, where

M11 = h 20! 3=2(b 11 ;a 11) i  M11 is an integer:

Remark 1.The initial data of the algorithm are an integerN, a real number ! ,! >1, and the interval matrix

A

=A+ 0b11 ;a

11] E

11: The algorithm has n stepsnM

11. We can compute the following real numbers 1= (

A

) = max j=01:::n;1 !(Aj) and r1=r(

A

) = min j=12:::n hj r1  1 20! 3=2:

The real numberr(

A

) is the smallest radius. As a result of the algo-rithm we have either the inequality!(

A

)1:25

1or the inequality

!(

A

) > ! with the answer \the interval matrix

A

is not practical discrete-time asymptotically stable".

(5)

5. Algorithm for a matrix with

m

interval entries

Let! be a real number! >1 and letAbe theNN matrix with the real entries aij. We de ne an interval matrix

A

with m interval entries by the equality

A

=A+ 0b11 ;a 11] E 11+:::+ 0bij ;a ij] E ij: The matrix

A

hasm interval entries in position (1,1),(2,1),:::(i; 1j), and (ij) m = i+ (j ;1)N. We include real numbers b

11,

b21,:::bi;1j, and bij in the initial data of the algorithm. In the sequel we also use the algorithm for checking practical discrete-time asymptoticstability of an interval matrixwith (m;1) interval entries. For m= 1 we have considered the algorithm of such kind in section 4. The algorithm for m2 is as follows.

1.

We assume that

A

0=A+ 0b11 ;a 11] E 11+:::+ 0bi;1j ;a i;1j] E i;1j and apply the algorithm to the interval matrix

A

0 with m

;1 interval entries. By this way, we can compute the real numbers

1= (

A

0) and r1 =r(

A

0). By the de nition, we have

1 ! and r 1  1 20! 3=2: If the inequalityaij+r1 b

ij holds then we stop the process with the answer!(

A

)<1:25 1. Otherwise, we go to Step 2.

2.

We assume that

A

1 =

A

0+r1Eij and apply the algorithm to the interval matrix

A

1 with (m

;1) interval entries. By this way, we can compute the real numbers 2 = (

A

1) and r2 = r(

A

1). By the de nition, we have

2 ! and r 2  1 20! 3=2: If the inequalityaij+r1+r2 b

ij holds then we stop the process with the answer !(

A

) < 1:25maxf

1 2

g. Otherwise, we go to Step 3.

After (p;1) steps of the process the real numbers

1 2::: p;1 and r1r2:::rp;1 are computed and for j = 12:::p

;1 we have j ! and r j  1 20! 3=2:

(6)

p.

We assume that

A

p;1=

A

0+(r1+r2+:::+rp;1)Eij and apply the algorithm to the interval matrix

A

p;1with (m

;1) interval entries. By this way, we can compute the real numbers p = (

A

p;1) and

rp =r(

A

p;1). By the de nition, we have

p ! and r p  1 20! 3=2: If the inequalityaij+r1+r2+:::+rp b

ij holds then we stop the process with the answer!(

A

)<1:25maxf

1 2::: p g. Other-wise, we go to Stepp+ 1. Sincerj 1=(20! 3=2) for

8jit followsthat we will stop the algorithm after not more then Mij steps, where

Mij = h 20! 3=2(b ij ;a ij) i  Mij is an integer:

Remark 2.The initial data of the algorithm are an integerN, a real number ! ,! >1, and the interval matrix

A

=A+ 0b11 ;a 11] E 11+:::+ 0bij ;a ij] E ij: The algorithm hasnstepsn

Q

Mij. We can compute the following real numbers = max j=12:::n j and r= min j=12:::n rj r  1 20! 3=2:

The real numberris the smallest radius. As a result of the algorithm we have either the inequality!(

A

)1:25 or the inequality!(

A

)>

! with the answer\the interval matrix

A

is not practical discrete-time asymptotically stable".

6. Conclusion

We have suggested the computer algorithm for checking the practical discrete-time asymptotic stability of an interval matrix.

References

1. Godunov, S.K. (1998): ModernAspectsofLinear Algebra, Transl. of Math.

Monographs, 175,AMS, Providence.

2. Bulgak, H. (1999): Pseudoeigenvalues, Spectral Portrait of a matrix and their connections with dierent criteria of stability, in: Error Control and Adap-tivity in Scientic Computing, Bulgak, H. and Zenger, C. (Eds.), Kluwer Academic Publishers, 95{124.

3. Bulgak, A. (2001): Checking a practical asymptotic stability of an interval matrix. Selcuk Journal of Applied Mathematics, Vol. 2, No. 1, 17{26.

Referanslar

Benzer Belgeler

Çivi yazısı kitabelerinde “Harranu (yol)” diye isimlendirilmesi, buranın ticaret merkezi olarak da önemini vurgulamaktadır. Büyük yolların kavşağında yani ticaret

6.56 (b) results in the transmission of a right-hand circularly polarized wave when the structure is illuminated by a normally incident wave with a polarization plane angle of π/4

Accordingly, the EU integration process of Kosovo is a perfect case to study horizontal coherence between different EU policies, the vertical coherence between the policies of

We carried out measurements of mm-wave excitation spectra of high- order whispering gallery modes in free-space cylindrical disk resonators as functions of resonator thickness L

Both covariance matrices and co-difference matrices are ex- tracted from randomly selected regions and added to the training set. Then the same procedure is also applied in the

East European Quarterly; Summer 2000; 34, 2; Wilson Social Sciences Abstracts pg... Reproduced with permission of the

We have shown that, just like Majoritarian Compromise, Median Rule satisfies Majoritarian Approval, Weak No Veto Power and Subgame Perfect Implementability, while it fails

rejected the conditional acceptance of the Vance-Owen plan and withheld support from the peace process.57 On 19 May, the Bosnian Croats and Bos- nian Muslims agreed to end hostili-