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4. Laplace Equation

In this section, Laplace equation with two independent variables

@

2

u

@x

2

+ @

2

u

@y

2

= 0 (1)

will be discussed and boundary value problems related to this equation will be examined. The equation (1) is usually expressed in the form

u = 0

with the help of Laplace operator which is given by

r

2

= = @

2

@x

2

+ @

2

@y

2

:

Some of the partial di¤erential equations which are expressed with the help of the Laplace operator and also which are of great importance in Mathematical Physics are as follows.

A. Two-dimensional Laplace equation u = 0 B. Poisson equation

u = q(x; y) C. Helmoltz equation

u + u = 0 ; is a positive constant D. Schrödinger equation (time independent)

u + [ q(x; y)] u = 0 E. Two-dimensional heat equation

u = 1 k

@u

@t

4.1. Boundary Value Problem

A boundary value problem is a problem of …nding a given partial di¤er- ential equation with certain boundary conditions. They are physically time- independent problems that only involve space coordinates. There are three types of boundary value problems and they are de…ned as follows.

I. Dirichlet Problem

1

(2)

It is the problem of …nding a function u(x; y) that is harmonic in a region D and satis…es the boundary condition

u = f (x; y) (2)

on the boundary C of D where f is a known function which is de…ned on the boundary C.

Figure 4.1. Planar region and boundary curve II. Neumann Problems

It is the problem of …nding a function u(x; y) that is harmonic in a region D and satis…es the boundary condition

@u

@n = f (x; y) (3)

on the boundary C of D. Here, @u

@n de…nes the outer normal derivative of u on C.

III. Robin Problem (Mixed Boundary Value Problem)

It is the problem of …nding a function u(x; y) that is harmonic in a D region and satis…es the boundary condition

@u

@n + h(x; y)u = g(x; y) (4)

on the boundary C of D. Here h and g are known functions given before.

4.2. Dirichlet Problem for a Rectangle

In this section, we will obtain the solution of the Dirichlet problem in a rectan- gular region R, which is a simple region of the plane. The best way to do this is to use the method of separation of variables. Let R be an open rectangular region in the xy-plane

R = f(x; y) : 0 < x < a ; 0 < y < bg :

2

(3)

Our problem is to …nd a function u(x; y) that satis…es the partial di¤erential equation

u

xx

+ u

yy

= 0 ; Inside R (5)

and the boundary conditions (Figure 7.2)

u(0; y) = 0 ; u(a; y) = 0 ; 0 y b

u(x; 0) = 0 ; u(x; b) = f (x) ; 0 x a : (6)

Figure 4.2. Dirichlet problem for a rectangle

According to the method of separation of variables, a trivial solution in the form of u(x; y) is obtained as follows

u(x; y) = X(x)Y (y) (7)

This solution must satisfy equation (5) and boundary conditions (6). We have the following solution

u(x; y) = X

1 n=1

b

n

sinh

n ya

sinh

n ba

sin n x

a : (8)

The values of the coe¢ cients b

n

in (8) are calculated by

b

n

= 2 a

Z

a

0

f (x) sin n x

a dx ; n = 1; 2; ::: (9)

Remark: The general Dirichlet problem de…ned in a rectangular region R = f(x; y) : 0 < x < a; 0 < y < bg is as follows.

u

xx

+ u

yy

= 0 ; Inside R

u(x; 0) = f

1

(x) ; u(x; b) = f

2

(x) ; 0 x a u(0; y) = f

3

(y) ; u(a; y) = f

4

(y) ; 0 y b

9 =

; (10)

3

(4)

For i = 1; 2; 3; 4, when the others f

i

are zero except for one of f

i

; the solution u

i

(1 i 4) of the problem in (10) is found by using the above method, and then the solution of (10) is obtained by adding the obtained four solutions u

1

; u

2

; u

3

and u

4

.

Example 1. Find the solution of the boundary value problem that satis…es u = 0 in R = f(x; y) : 0 < x < ; 0 < y < g and satis…es the conditions u(0; y) = 0; u( ; y) = 0; u(x; 0) = 0; u(x; ) = sin

3

x:

Solution: By trigonometric identities, we can write f (x) = sin

3

x = 3

4 sin x 1 4 sin 3x:

From (8), the solution to the problem is found

u(x; y) = X

1 n=1

b

n

sinh ny sinh n sin nx and the coe¢ cients b

n

are obtained by

b

n

= 2 Z

0

f (x) sin nx dx ; n = 1; 2; :::

or

f (x) = sin

3

x = 3

4 sin x 1

4 sin 3x = X

1 n=1

b

n

sin nx

b

1

= 3

4 ; b

3

= 1

4 ; b

n

= 0 (for all other n) Thus, the desired solution is found as

u(x; y) = 3 4

sinh y

sinh sin x 1 4

sinh 3y sinh 3 sin 3x:

4

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