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Available online at www.atnaa.org Research Article

The continuity of solution set of a multivalued equation and applications in control problem

Tran Thanh Phonga, Vo Viet Tria

aDivision of Applied Mathematics, Thu Dau Mot University, Binh Duong Province, Vietnam.

Abstract

In this paper, we prove the existence, unbounded continuity of positive set for a multivalued equation containing a parameter of the form x ∈ A ◦ F (λ, x) and give applications in the control problem with multi-point boundary conditions and second order derivative operator

u00(t) + g(λ, t)f (u(t)) = 0, t ∈ (0, 1), g(λ, t) ∈ F (λ, u(t)) a.e. on J

u(0) = 0, u(1) =Pm

i=1αiu(ηi)

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Keywords: multivalued operator, multivalued equation, xed point index, control problem.

1. Introduction

The single-valued equation of the form x = F (λ, x) in ordered spaces has been studied for a long time by many mathematician researchers and has found many successful results (see [2, 3, 4, 11, 13, 17]). It was naturally generalized to multivalued form

x ∈ F (λ, x). (2)

There are many good methods approaches available, among them are principal eigenvalue - eigenvector method (see impressive results of J. R. L. Webb and K. Q. Lan in [17], Guy Degla in [2]), monotone minorant method [7, 8], the method of using the denition of topological degree (the xed point index) for

Email addresses: phongtt.khtn@tdmu.edu.vn (Tran Thanh Phong), trivv@tdmu.edu.vn (Vo Viet Tri) Received March 23, 2021; Accepted: April 30, 2021; Online: May 02, 2021.

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single-valued/multivalued mappings [1, 5, 9, 12, 14, 15, 16] and the method of combining two latter methods [8].

The solution set of (2) is well-known in two following forms

S = {(λ, x) : x ∈ F (λ, x)}, (3)

or

S = {x : ∃λ, x ∈ F (λ, x)}. (4)

In this paper, we prove the existence, unbounded continuity of the solution set S of the form (4), with the equation x ∈ A ◦ F (λ, x), where F is a multivalued function containing a parameter λ and A is a linear mapping. We establish sucient conditions for the set S to be unbounded continuous branch and emanating from zero, i.e., it contains the elements of S on the boundary of any set Ω, which is open, bounded, and contains zero.

Our method is to combine the method of using the denition of topological degree for multivalued mapping and the method of evaluating solutions. The others authors using only one. This is the fundamental dierence between our work and the authors mentioned above.

By the abstract result obtained, we apply for the control problem with second order derivative and multi- point boundary conditions. The such problem has attracted the increasing attention of many researchers.

We will solve this problem to illustrate the method.

The paper is organized as follows. In Section 2, we recall some notations and useful lemma. In Section 3, the main results are stated. In Section 4, we present the existence of solutions to the control problem.

2. Preliminaries

Let (E, K, k.k) be a real Banach space ordering by the cone K, i.e., K is a closed convex subset of E such that λK ⊂ K for λ ≥ 0, K ∩ (−K) = {0}, and x ≤ y i y − x ∈ K for x, y ∈ X. For nonempty subsets A, B of E we write A <2 B (or, B 42A) i for every x ∈ A, there exists y ∈ B satisfying x ≥ y (or, y ≤ x) and we also write A 41 B i for every x ∈ A, there exists y ∈ B such that x ≤ y. The cone K is said to be normal if there exists a constant N > 0 such that 0 ≤ x ≤ y implies kxk ≤ Nkyk. Throughout this article we always assume that K is normal cone with N = 1. For A ⊂ E, the all nonempty closed convex (resp., closed) subsets of A is denoted by cc(A) (resp., c(A)). Let Ω be an open subset of E, denote ΩK = K ∩ Ω,

KΩ = K ∩ ∂ΩandK = K\{0} , where ∂Ω is the boundary of Ω in E. A mapping T : K ∩Ω → cc(K) is said to be compact i T (B) is relatively compact for any bounded subset B of K ∩ Ω, where T (B) = ∪x∈BT (x). T is called upper semicontinuous (in short, u.s.c.) if {x ∈ K ∩ Ω : T (x) ⊂ W } is open in K ∩ Ω for every open subset W of K. Further, if x /∈ T (x) for all x ∈ ∂KΩ, the xed point index of T in Ω with respect to K is dened which is an integer denoted by iK(T, Ω) (see e.g. [5]). The following lemma on the computation of the index were taken in [5, proof of Theorem 3.2].

Lemma 2.1. [8, 5, proof of Theorem 3.2] Let T : K ∩ Ω → cc(K) be an u.s.c. compact multivalued operator.

Then

1. iK(T, Ω) = 0if there exists u ∈K such that x /∈ T (x) + ku for all x ∈ ∂KΩ and k ≥ 0.

2. iK(T, Ω) = 1if kx /∈ T (x) for all k ≥ 1.

We review the results using to prove our abstract results.

Lemma 2.2. [6, Proposition 2.22] Assume that T : D ⊂ E → c(E) is an u.s.c. multivalued operator and a net (x, y) → (x, y) with y ∈ T (x). Then y ∈ T (x).

Lemma 2.3. [5, Theorem 2.1] Assume that multivalued operator H : [0, 1]×K ∩Ω → cc(K) is u.s.c. compact satisfying x /∈ H(t, x) for all (t, x) ∈ [0, 1] × ∂KΩ. Then, iK(H(0, .), Ω) = iK(H(1, .), Ω).

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3. Abstract results

Lemma 3.1. Let T : [0, ∞) × K → cc(K) be an u.s.c compact operator and Ω 3 0 be an open bounded subset of E. Assume that the following conditions are satised

1. tx ∈ T (0, x) for some x ∈K implies t < 1,

2. there exists λ0 > 0 such that ik(T (λ, .), Ω) = 0 for all λ ≥ λ0. Then the set {x ∈ ∂KΩ : ∃λ > 0, x ∈ T (λ, x)}is nonempty.

Proof. We dene

α = sup{λ > 0 : iK(T (λ, .), Ω) 6= 0}

It is clear that α > 0. Indeed, assume that the following assertion holds

∀ > 0, ∃(t, x) ∈ [0, 1] × ∂KΩ : x ∈ (1 − t)T (, x) + tT (0, x). (5) Since T is compact, without loss of generality we may assume that t → t, x → xwhen  → 0. From (5) by Lemma 2.2 it follows that

x ∈ (1 − t)T (0, x) + tT (0, x) ⊂ T (0, x).

This contradicts the rst condition. Thus, there exists  > 0 such that (t, x) /∈ H(t, x) for all (t, x) ∈ [0, 1] × ∂KΩ, where

H(t, x) = (1 − t)T (, x) + tT (0, x).

Using Lemma 2.3 we have

iK(T (0, .), Ω) = iK(T (, .), Ω).

By Lemma 2.1 from the rst condition it follows iK(T (0, .), Ω) = 1. Thus iK(T (, .), Ω) = 1, we deduce λ0 > α ≥  > 0.

Next, for any  ∈ (0, α), there exists λ∈ (α − , α] with iK(T (λ, .), Ω) 6= 0. Consider multivalued operator H dened by

H(t, x) = (1 − t)T (λ, x) + tT (α + , x).

Now, we prove

{x ∈ ∂KΩ : ∃λ > 0, x ∈ T (λ, x)} 6= ∅.

Assume on the contrary, that

{x ∈ ∂KΩ : ∃λ > 0, x ∈ T (λ, x)} = ∅. (6) Then, the xed point index of T (α + , .) is well dened and it is equal 0 from the denition of α. If

x /∈ H(t, x) for all (t, x) ∈ [0, 1] × ∂KΩ, (7) by Lemma 2.3 we obtain

iK(T (λ, .), Ω) = iK(T (α + , .), Ω). (8) This is a contradiction. Therefore (7) is impossible, i.e., there is (t, x) ∈ [0, 1] × ∂KΩsatisfying

x ∈ (1 − t)T (λ, x) + tT (α + , x). (9) By an argument analogous to the previous one we can nd x ∈ ∂KΩwith x ∈ T (α, x). This contradicts (6).

The proof is complete. 

Let (Y, KY, k.kY) be a Banach space, ordered by normal cone KY. Suppose that E ⊂ Y, K ⊂ KY ∩ E, embedding (E, k.k) ,→ (Y, k.kY) is continuous, and F : [0, ∞) × K → cc(KY) is u.s.c. compact multivalued operator. Let A : Y → X be a compact linear operator satisfying A(KY) ⊂ K.

Theorem 3.1. Assume that the following conditions are satised

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1. kx ∈ A ◦ F (0, x) for some x ∈K implies k < 1;

2. there are positive numbers a, b, c and a linear function L : Y → R+ with L(y) 6= 0 for some y ∈ K such that

(a) LAx <2{aLx} and LAx <2 {a.kAxkY} for all x ∈ KY, (b) L(F (λ, x)) <2{bλLx − c}for all x ∈ K, and

(c) there exists a function h : R+× R+→ R increasing on the second variable with

λ→∞lim h(λ, c

abλ − 1) = 0 (10)

such that (k, λ, x) ∈ [0, 1] × [0, ∞) × K with

x ∈ kA ◦ F (λ, x) + (1 − k)bλAx (11)

implies

kxk ≤ h(λ, kxkY). (12)

Then, S = {x ∈K : ∃λ > 0, x ∈ A ◦ F (λ, x)} is unbounded continuous branch emanating from 0.

Proof. Let Ω 3 0 be an open bounded subset of E. We will apply Lemma 3.1 with T (λ, x) = A ◦ F (λ, x) to prove S ∩ ∂KΩ 6= ∅. Clearly, the condition 1. of the lemma holds. Assume that (k, λ, x) ∈ [0, 1] × [0, ∞) × K satised (11), it is obvious that x ∈ A[kF (λ, x) + (1 − k)bλx], hence x = A[kyλ+ (1 − k)bλx] for some yλ ∈ F (λ, x). From 2(a) and 2(b) applying the operator L we have

Lx ≥ aL(kyλ+ (1 − k)bλx) ≥ a(bλLx − c), (13)

Lx ≥ akA[kyλ+ (1 − k)bλx]kY = akxkY. (14)

We always assume λ is suciently large, from (13) and (14) if follows that kxkY ≤ c

abλ − 1 which together with (12) gives

kxk ≤ h(λ, c

abλ − 1). (15)

If x ∈ ∂KΩ, bkxk >  > 0 for some . From (15), (11) and (12) it follows that

x /∈ H(k, x) for all (k, x) ∈ [0, 1] × ∂KΩ, (16) where H(k, x) = kA ◦ F (λ, x) + (1 − k)bλAx, partially, x 6= bλAx.

Applying Lemma 2.3 we obtain iK(T (λ, .Ω)) = iK(λbA, Ω). Choose u ∈K with Lu > 0. We now prove that x 6= bλAx + su for all (s, x) ∈ [0, ∞) × ∂KΩ. (17) Assume on the contrary, that exists (s, x) ∈ [0, ∞) × ∂KΩsatisfying

x = bλAx + su. (18)

This implies s > 0. Acting the operator L to both sides of (18) from the condition 2(b) we obtain (1 − abλ)Lx ≥ su, this is impossible. Therefore, from Lemma 2.1 it follows iK(bλA, Ω) = 0. We deduce iK(T (λ, .), Ω) = 0. The proof is complete. 

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4. Applications

Let F : [0, ∞) × R+ → cc(R+) be an u.s.c. compact multivalued operator and f : R+ → R+ be a continuous function. Denote J = [0, 1]. We consider control problem which contains a parameter of the form

u00(t) + g(λ, t)f (u(t)) = 0, t ∈ (0, 1), g(λ, t) ∈ F (λ, u(t)) a.e. on J

u(0) = 0, u(1) =Pm

i=1αiu(ηi)

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where, 0 < ηi < 1, αi ≥ 0,Pm

i=1αiηi < 1.

Denote Λ = Pmi=1αiηi. for every (t, s) ∈ [0, 1] × [0, 1], we dene

h(t, s) =

(s(1 − t), s ≤ t, t(1 − s), s > t.

G(t, s) = t 1 − Λ

m

X

i=1

αih(ηi, s) + h(t, s);

Let C(J) and C1(J ), resp., be the Banach spaces of all continuous and continuous dierentiable function on J. Denote E = x ∈ C1(J ) : x(0) = 0

, and Y = {x ∈ C(J) : x(0) = 0}. Let A : Y → E be a compact linear operator dened by

A(u)(t) = Z 1

0

G(t, s)u(s)ds, t ∈ J (20)

Instead of solving problem (20) we shall consider its equivalent form

x ∈ A ◦ T (λ, x), (21)

where the multivalued operator T is dened by

T (λ, x)(t) = F [λ, x(t)]f [x(t)], t ∈ J.

Theorem 4.1. Let ρ =n

supt∈JR1

0 G(t, s)dso−1

. Assume that there exist numbers α > 0, β > 0, γ ∈ (0, ρ) and r ∈ (0, 2) such that

1. F (0, x)f(x) 41 γx ∀x > 0, 2. αλx − β 42F (λ, x)f (x),

3. F (λ, x) 411 + λr2|x|r for all (λ, x) ∈ (0, +∞) × R+.

Then, the set S of positive solutions for (21) is unbounded continuous in C1(J ), emanating from 0.

Proof. We shall apply Theorem 3.1 with the cone

K = {x ∈ E : x(t) ≥ 0 ∀t ∈ J }, the cone

KY = {x ∈ Y : x(t) ≥ 0 ∀t ∈ J }.

Then, Y and E, resp., are Banach spaces with the norms kxkY = sup

t∈J

|x(t)|

and

kxk = kx0kY.

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Suppose x ∈K and k satises kx ∈ A ◦ T (0, x), we can nd u(s) ∈ F (0, x(s)) such that

|kx(t)| =

Z 1 0

G(t, s)u(s)f (x(s))ds ,

≤ γkxkY

Z 1 0

G(t, s)ds

≤ kxkY ∀t ∈ J.

This implies k < 1. From the well-known results in [17], the compact linear operator A has an eigen- value µ0 > 0 with respect to a positive eigen-function u0. We dene the linear operator L on Y , by Lx =R1

0 x(s)u0(s)ds. From the condition 2, we have L(T (λ, x)) <2

Z 1 0

(αλx(s) − β)u0(s)ds

≥ αλLx − c,

where c = β R01u0(s)ds. If y is non-negative continuous concave function on J satisfying y(0) = 0 and y(1) ≥ 0, there exists number ξ > 0 such that y(t) ≥ ξkykYu0(t)on J. For x ∈ KY, Ax is concave function with Ax(0) = 0 and Ax(1) ≥ 0, we have Ax(t) ≥ ξkAxkYu0(t). From Fubini's Theorem it follows that

L(Ax) = Z 1

0

Z 1 0

G(t, s)x(s)ds



u0(t)dt

= Z Z

J ×J

G(t, s)x(s)u0(t)dsdt

= Z 1

0

Z 1 0

G(t, s)u0(t)dt

 x(s)ds

= Z 1

0

Au0(s)x(s)ds

= µ0

Z 1 0

u0(s)x(s)ds

= µ0Lx.

Consequently, there is constant a > 0 satisfying

L(Ax) ≥ aLx and L(Ax) ≥ akAxkY. (22)

Now, assume (k, λ, x) ∈ [0, 1] × [0, ∞) × K with

x ∈ kA ◦ T (λ, x) + (1 − k)αλAx. (23)

This implies

− x00 ∈ kT (λ, x) + (1 − k)αλx. (24)

In the following the numbers mj, j = 0, 1, 2, .., 6 and m are constant numbers, not depending on λ, x and t ∈ J. By a similar argument as the proof of Theorem 3.1 we obtain

kxkY ≤ c

aαλ − 1. (25)

Therefore we can choose m1 such that

λkxkY ≤ m1 (26)

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From (26), the well-known inequality

kx0k2Y ≤ m2kxkY.kx00kY. (27)

and (24) we obtain

kx00kY ≤ m3(1 + λr2kxkrY) + αm1 (28)

≤ m4(1 + λr2kxkrY). (29)

Further, for x ∈ K, we have kxkY ≤ m0kx0kY. Combining this inequality, (26), (27), (29) and (29) we have kx00kY ≤ m5(1 + kx00k

r 2

Y) ≤ m6. (30)

From (27) we can choose m such that kx0kY ≤ mkxk

1 2

Y. Since kxk = kx0kY, the condition (2c) of Theorem 3.1 are satised with function h(λ, t) = mt12. 

5. Conclusion

In this paper, the unbounded continuity of positive solution set for a multivalued equation containing a parameter has established and given the application in the control problem with multi-point boundary conditions.

Acknowledgments

This reseach was supported by Thu Dau Mot university.

References

[1] A. Cellina and A. Lasota, A new approach to the denition of topological degree for multivalued mappings, Lincei Rend.

Sc. Mat. e Nat., 47 (1969), 434440.

[2] G. Degla, On the Principal Eigenvalue of Disconjugate BVPs with L1-Coecients, Advanced Nonlinear Studies 2, (2002), 1939.

[3] M. Gardasevic-Filipovic, K. Kukic, Z. Mitrovic, S. Radenovic, Review of the convex contractions of Istratescu's type in various generalized metric spaces, Advances in the Theory of Nonlinaer Analysis and its Application, 4(3), 2020, 121131.

[4] B. Feng, H.C. Zhou, X.G. Yang, Uniform boundness of global solutions for a n-dimensional spherically symmetric combus- tion model, Applicable Analysis, 98(15), (2019), 26882722.

[5] P.M. Fitzpatrick and W.V. Pettryshyn, Fixed point theorems and the xed point index for multivalued mappings in cones, J. London Math. Soc. (2), 12 (1975), 7585.

[6] S. Hu, N.S. Papageorgiou, Handbook of Multivalued Analysis, Vol. I, Kluwer, 1997.

[7] N.B. Huy, Global Continua of Positive Solution for Equations with Nondierentiable operators, 239(1999), 449456.

[8] N.B. Huy, T. T. Binh and V.V. Tri, The monotone minorant method and eigenvalue problem for multivalued operators in cones, Fixed Point Theory, 19(1), (2018), 275286.

[9] L. Lia, D. Wua, The Convergence of Ishikawa Iteration for Generalized Φ-contractive Mappings, Results in Nonlinear Analysis 4(1) 2021, 4756

[10] T.W. Ma, Topological degrees for set-valued compact vector elds in locally convex spaces, Dissertationes Math., 92 (1972), 143

[11] S. Moradi, New Fixed Point Theorem for generalized TFcontractive Mappings and its Application for Solving Some Polynomials, Advances in the Theory of Nonlinear Analysis and its Applications 4(3), 2020, 167175.

[12] W.V. Petryshyn, P.M. Fitzpatrick, A Degree Theory, Fixed Point Theorems, and Mapping Theorems for Multivalued Noncompact Mappings, Transactions of the American Mathematical Society, 194 (1974), 125.

[13] J. Mathuraiveerana, S. Mookiahb, Common Fixed Point Theorems in M-Fuzzy Cone Metric Spaces, Results in Nonlinear Analysis 4(1), 2021, 3346.

[14] V.V. Tri and Erdal Karapinar, A Fixed Point Theorem and an Application for the Cauchy Problem in the Scale of Banach Spaces, Filomat, 34(13),2020, 43874398.

[15] V.V. Tri and Shahram Rezapour, Eigenvalue Intervals of Multivalued Operator and its Application for a Multipoint Boundary Value Problem, BIMS, https://doi.org/10.1007/s41980-020-00451-0.

[16] V.V. Tri, positive Eigen-Pair of dual operator and applications in Two-Player game control, DSA, 30 (2021) No.1, 7990.

[17] J.R.L. Webb and K.Q. Lan, Eigenvalue criteria for existence of multiple positive solutions of nonlinear boundary value problems of local and nonlocal type, Topological Methods in Nonlinear Analysis, 27 (2006), 91115.

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