• Sonuç bulunamadı

Başlık: On quasi-statistical convergenceYazar(lar):SAKAOĞLU ÖZGÜÇ, İ; YURDAKADİM, T.Cilt: 61 Sayı: 1 Sayfa: 011-017 DOI: 10.1501/Commua1_0000000674 Yayın Tarihi: 2012 PDF

N/A
N/A
Protected

Academic year: 2021

Share "Başlık: On quasi-statistical convergenceYazar(lar):SAKAOĞLU ÖZGÜÇ, İ; YURDAKADİM, T.Cilt: 61 Sayı: 1 Sayfa: 011-017 DOI: 10.1501/Commua1_0000000674 Yayın Tarihi: 2012 PDF"

Copied!
7
0
0

Yükleniyor.... (view fulltext now)

Tam metin

(1)

IS S N 1 3 0 3 –5 9 9 1

ON QUASI-STATISTICAL CONVERGENCE

·

I. SAKAO ¼GLU ÖZGÜÇ AND T. YURDAKAD·IM

Abstract. The sequence x = (xk)is quasi-statistically convergent to L

pro-vided that for each " > 0, lim

n

1

cnjfk n : jxk Lj "gj = 0 where limn

cn= 0;

cn > 0 for each n 2 N and lim sup n

cn

n < 1: In this paper quasi-statistical convergence is compared with statistical convergence and other methods. Fur-thermore a decomposition theorem is proved and a factorization result is also given for quasi-statistical convergence.

1. Introduction

A number sequence x = (xk) is said to be statistically convergent to the number L

if for every " > 0; lim

n

1

njfk n : jxk Lj "gj = 0 where the vertical bars indicate the number of elements in the enclosed set. In this case we write st lim x = L or xk! L (st) ([1], [2] and [10]). By S we denote the set of all statistically convergent

sequences. This type of convergence method is quite e¤ective, especially when the classical limit does not exist.

In [7] Ganichev and Kadets have de…ned the quasi-statistical …lter. Motivating by their de…nition of quasi-statistical …lter, we introduce quasi-statistical conver-gence and study the relationship between quasi-statistical converconver-gence and statisti-cal convergence. A decomposition theorem is also proved along with a factorization result for quasi-statistical convergence.

If K is a set of positive integers, jKj will denote the cardinality of K. The natural density of K is given by

(K) = lim

n!1

1

njfk n : k 2 Kgj , if it exists.

Received by the editors Jan 17, 2012, Accepted: May 04, 2012.

2000 Mathematics Subject Classi…cation. Primary 40A35 ; Secondary 40G15, 40F05. Key words and phrases. statistical convergence, statistical convergence, strong quasi-summability, multipliers.

c 2 0 1 2 A n ka ra U n ive rsity

(2)

The number sequence x = (xk) is statistically convergent to L provided that for

every " > 0 the set K"= fk 2 N : jxk Lj "g has natural density zero. In this

case we write st lim x = L.

Throughout the paper we assume that c := (cn) is a sequence of positive real

numbers such that

lim

n cn = 1 and lim supn

cn

n < 1: (1.1)

We de…ne the quasi-density of E N corresponding to the sequence (cn) by c(E) := lim

n

1

cn jfk n : k 2 Egj

if it exists.

The sequence x = (xk) is called quasi-statistically convergent to L provided that

for every " > 0 the set E"= fk 2 N : jxk Lj "g has quasi-density zero. In this

case we write stq lim x = L or xk! L (stq):

The next result establishes the relationship between quasi-statistical convergence and statistical convergence.

Lemma 1.1. If x = (xk) is quasi-statistically convergent to L then it is statistically

convergent to L:

Proof. Let stq lim x = L and H := sup n cn n: Since 1 njfk 2 N : jxk Lj "gj H cn jfk 2 N : jx k Lj "gj

the proof follows immediately.

We give an example in order to show that the converse of Lemma 1.1 does not hold.

Example 1.2. Let c := (cn) be the sequence of positive real numbers such that

lim

n cn = 1, and limn

p n

cn = 1: We can choose a subsequence c

np such that

cnp> 1 for each p 2 N:

Consider the sequence x = (xk) de…ned by

xk:= 8 < : ck ; k is square and ck2 cnp: p 2 N 2 ; k is square and ck2 c= np: p 2 N 0 ; otherwise.

It is easy to see that x is statistically convergent to zero. Now we show that x is not quasi-statistically convergent to zero.

(3)

Let " = 1: 1 cnjfk 2 N : jxkj 1gj = 1 cn p n (1.2) = 1 cn (pn tn)

where 0 tn< 1 for each n 2 N: Letting n ! 1 in both sides of (1.2), we observe

that x is not quasi-statistically convergent to zero.

The following result relates the statistical convergence to quasi-statistical con-vergence.

Lemma 1.3. Let c := (cn) be the sequence of positive real numbers satisfying (1.1)

and

d := inf

n

cn

n > 0 (1.3)

If x = (xk) is statistically convergent to L then it is quasi-statistically convergent

to L:

Proof. The result follows from the inequality: 1

njfk 2 N : jxk Lj "gj d 1

cnjfk 2 N : jx

k Lj "gj :

Note that the condition given by (1.3) can not be omitted.

By Lemma 1.1 and Lemma 1.3, the next result follows immediately.

Theorem 1.4. Let c := (cn) be the sequence of positive real numbers satisfying

(1.1) and (1.3). Then x = (xk) is statistically convergent to L if and only if x is

quasi-statistically convergent to L:

By Sq, we denote the set of all quasi-statistically convergent sequences.

It is easy to see that every convergent sequence is quasi-statistically convergent, i.e., c Sq where c is the set of all convergent sequences.

2. Strong Quasi-Summability

In this section, introducing the strong quasi-summability, one of our purpose is to study inclusion theorems between statistical convergence and strong quasi-summability. From [3], [4] and [9] we know that there is a natural relationship between statistical convergence, Cesàro summability and strong Cesàro summabi-lity.

The sequence x = (xk) is said to be strongly quasi-summable to L if

lim n 1 cn n X k=1 jxk Lj = 0:

(4)

The space of all strongly quasi-summable sequences is denoted by Nq:

Nq:=

(

x : for some L, lim

n 1 cn n X k=1 jxk Lj = 0 ) :

Theorem 2.1. Let c := (cn) be the sequence of positive real numbers satisfying

(1.1). If x is strongly quasi-summable to L then it is quasi-statistically convergent to L:

Proof. Let x = (xk) such that stq lim x = L:

1 cn n X k=1 jxk Lj 1 cn n X k=1 jxk Lj " jxk Lj " cnjfk n : jxk Lj "gj

which concludes the proof.

Schoenberg showed that a bounded statistically convergent sequence is Cesàro summable [9]. Combining this result with Lemma 1.1 the following corollary follows easily.

Corollary 1. Let x be a bounded sequence and a quasi-statistically convergent to L: Then x is Cesàro summable to L:

Theorem 2.2. Let x be a bounded sequence and a quasi-statistically convergent to L; and let (1.1) and (1.3) hold. Then x is strongly quasi-summable to L:

Proof. The result follows from the inequality:

1 cn n X k=1 jxk Lj < " n cn + M 1 cn jfk n : jxk Lj "gj

where jxk Lj M; for every k 2 N since x is bounded.

The next result is the decomposition theorem for quasi-statistical convergence which is an anolog of the decomposition theorem on statistical convergence ([2], [3], [8]).

Theorem 2.3. If x is quasi-statistically convergent to L, then there is a sequence y which converges to L and quasi-statistically null sequence z such that x = y + z. Proof. Let x be a quasi-statistically convergent sequence.

We can …nd an increasing sequence of positive integers (Nj) such that

N0= 0 and 1 cn k n : jxk Lj 1 j < 1 j; n > Nj (j = 1; 2; :::): Let us de…ne y = (yk) and z = (zk) as follows;

(5)

zk = 0 and yk = xk ; if N0< k N1 zk = 0 and yk = xk ; if jxk Lj < 1 j , Nj < k Nj+1; for j 1 zk = xk L and yk = L ; if jxk Lj 1 j , Nj < k Nj+1; for j 1 It is easy to see that x = y + z.

Now we show that y is convergent to L:

Given " > 0: Let j such that " > 1j: If jxk Lj 1j; k > Nj;

then jyk Lj = jL Lj = 0. If jxk Lj < 1j; then jyk Lj = jxk Lj < 1j < ".

Therefore

lim

k!1yk = L:

To show that z is quasi-statistically null sequence; it is enough to prove

lim

n!1

1 cnjfk

n : zk 6= 0gj = 0:

We know, for " > 0; that

fk n : jzkj "g fk n : zk6= 0g :

Thus

jfk n : jzkj "gj jfk n : zk6= 0gj :

If 1

j < for > 0 and j 2 N, we show that 1

njfk n : zk6= 0gj < for all

n > Nj.

In this case zk 6= 0 if and only if jxk Lj 1j, Nj< k Nj+1:

If Nj< k Nj+1, then

fk n : zk6= 0g = k n : jxk Lj

1 j :

Thus if Nv< k Nv+1 and v > j, then

1 cnjfk n : zk 6= 0gj 1 cn k n : jxk Lj 1 v < 1 v < 1 j < which concludes the proof.

The following result is an immediate consequence of Theorem 2.3.

Corollary 2. If x is quasi-statistically convergent to L, then x has a subsequence y such that y converges to L:

The following two Tauberian results follow from Theorems 3 and 5 of [2] and the present Lemma 1.1:

Theorem 2.4. If x is a sequence such that x is quasi-statistically convergent to L and xk = o(1k) then x is convergent to L where xk = xk xk+1:

(6)

Theorem 2.5. Let fk(i)g1i=1 be an increasing sequence of positive integers such

that lim inf

i

k(i + 1)

k(i) > 1, and let x be a corresponding gap sequence: xk = 0 if k 6= k(i) for each i 2 N; if x is quasi-statistically convergent to L then x is convergent to L:

3. Multipliers

This section is devoted to multipliers and factorization problem. Connor, Demirci and Orhan ([5], [6]) studied multipliers for bounded statistically convergent se-quences. Following their idea, we get similar results for quasi-statistically conver-gent sequences.

Assume that two sequence spaces, E and F are given. A multiplier from E into F is a sequence u such that ux = (unxn) 2 F whenever x 2 E: The linear space of

such multipliers will be denoted by m(E; F ):

Theorem 3.1. x 2 m(stq; stq) if and only if x 2 stq:

Proof. Necessity: Let u 2 m(stq; stq): Then we have ux 2 stq for an arbitrary

x 2 stq: Hence we can choose x = N2 stq then ux = u 2 stq:

Su¢ ciency: Let x 2 stq; y 2 stq: Considering the inequality

jfk 2 N : jxkykj "gj k 2 N : jxkj p" + k 2 N : jykj p" ;

we obtain xy 2 stq; i.e., x 2 m(stq; stq):

Theorem 3.2. x 2 m(Nq; stq) if and only if x 2 stq:

Proof. Necessity: Let u 2 m(Nq; stq): Then we have ux 2 stq for an arbitrary

x 2 Nq: Hence we can choose x = N2 Nq then ux = u 2 stq:

Su¢ ciency: Let x 2 stq and y 2 Nq: Using Theorem 2.1 and Theorem 3.1 we have

x 2 m(Nq; stq):

We shall be interested in sequences x that admit a factorization x = yz

in which

y 2 stq and z 2 Nq:

Theorem 3.3. x is a quasi-statistically convergent sequence if and only if there is a strongly quasi-summable sequence y and quasi-statistically convergent sequence z such that x = yz.

Proof. Necessity: Let x 2 stq: Since N2 Nq; we have x = Nx 2 Nq:stq:

Su¢ ciency: Let y 2 Nq and z 2 stq such that x = yz: It follows from Theorem 3.2

(7)

ÖZET: Her n 2 N için cn > 0; lim

n cn = 0 ve lim supn

cn

n < 1 olmak üzere her " > 0 için lim

n

1

cnjf k n : jxk Lj "gj = 0

ise (xk) dizisi L say¬s¬na quasi-istatistiksel yak¬nsakt¬r denir. Bu

çal¬¸smada quasi-istatistiksel yak¬nsakl¬k, istatistiksel yak¬nsakl¬k ve di¼ger metodlarla kar¸s¬la¸st¬r¬lm¬¸st¬r. Ayr¬ca quasi-istatistiksel yak¬nsakl¬k için bir ayr¬¸st¬rma teoremi ve bir faktorizasyon prob-lemi incelenmi¸stir.

References

[1] H. Fast, Sur la convergence statistique, Colloq. Math. 2 (1951) 241-244. [2] J. A. Fridy, On statistical convergence, Analysis 5 (1985) 301-313.

[3] J. Connor, The statistical and strong p-Cesàro convergence of sequences, Analysis 8 (1988) 47-63.

[4] J. Connor, On strong matrix summability with respect to a modulus and statistical conver-gence, Canad. Math. Bull., 32 (1989) 194-198.

[5] J. Connor, K. Demirci and C. Orhan, Multipliers and factorization for bounded statistically convergence sequences, Analysis (Munich) 22 no:4 (2002) 321-333.

[6] K. Demirci and C. Orhan, Bounded multipliers of bounded A-statistically convergent se-quences, Journal of Mathematical Analysis and Applications 235 (1999) 122-129.

[7] M. Ganichev and V. Kadets, Filter convergence in Banach spaces and generalized bases, Taras Banach (Ed.), General Topology in Banach Spaces, NOVA Science Publishers, Huntington, New York (2001) 61-69.

[8] T. Šalát, On statistically convergent sequences of real numbers, Math. Slovaca 30, no.2 (1980) Math. 139-150.

[9] I. J. Schoenberg, The integrability of certain functions and related summability methods, Amer. Math. Monthly, 66 (1959) 361-375.

[10] H. Steinhaus, Sur la convergence ordinarie et la convergence asymtotique, Colloq. Math. 2 (1951) 73-74.

Current address : ·I. Sakao¼glu Özgüç and T. Yurdakadim; Ankara University, Faculty of Sci-ences, Dept. of Mathematics, Ankara, TURKEY

E-mail address : i.sakaoglu@gmail.com, tugba-yurdakadim@hotmail.com URL: http://communications.science.ankara.edu.tr/index.php?series=A1

Referanslar

Benzer Belgeler

KHA’sı olan hastalar, tipik olarak saf demir eksikliği anemisi olanlardan daha yüksek ferritin konsantrasyonuna sahiptir.. RA’lı hastalarda DEA tanısı koymak bazen

Teorik olarak bir küp şekli üzerinde konumlanan kristal birim kafes yapılarıdır. Bu yapılar doğada kristal ve minerallerin atomik dizilişinde ve dış yapısında

Toplam 30 maddeye sahip olan öğretmenlerin eğitim programı tasarım yaklaşımı tercih ölçeği ilköğretim ve lise öğretmen- lerine uygulanmış ve yapılan açımlayıcı

Çocuğun, ailenin bir üyesi olarak kişiliğini, toplumsal davranışlarını, değerlerini, ahlak yargılarını, aile içerisinde aldığı eğitim ve terbiye, kabul edilen

Turfanda’nın koreografilerini gerçekleştirdiği baleler arasında, ‘Yoz Döngü’, ‘Güzelleme’, ‘Telli Turna’, ‘Hürrem Sultan’, ‘Kamelyalı

component wise. Example 2.1: The following matrix,.. These two examples show that some infinite matrices preserve the limit of a sequence but some of them does not. This

New type of convergences like statistical convergence, λ−statistical convergence, Lacunary sta- tistical convergence and more generally αβ−statistical convergence are all

Ayrıca, tanıtılan bu yeni kavram ile daha önceden küme değerli diziler için verilen Wijsman quasi-hemen hemen yakınsaklık ve Wijsman quasi-hemen hemen istatistiksel