Development Of A Nodal Method
For The Solution Of The Neutron
Diffusion Equation In Cylindrical
Geometry
Mehmet MERCIMEK
Istanbul Technical University Energy Institute
NODAL FORMALISM
1. The multigroup neutron balance equation
r r , g 1,2, ,G k r r r r r J G 1 g g g f g 1 g 1 g g g g g g r g
2. Fick’s Law
r D
r
r J g g g Basis of nodal formalism:
r
r r Q
r J r Nodal Mesh
Decompose the reactor core into relatively large
subregions (nodes) in which the material composition and flux are assumed uniform.
Cell and Edge Averaged
Quantities
Edge-based
unknowns
ir 1/2 1/2 ir 2 1/2 -i 2 1/2 i ir
rdr
)
r
(r
2
ir 1/2 1/2 -ir r 2 1/2 -i 2 1/2 i iQ(r)rdr
)
r
r
(
2
Q
The
cell-based
unknownsΦi+1/2, Φi-1/2 and Ji+1/2, Ji-1/2
Relationships between
edge-based quantities
Under P1 Approximation
2 r J n 4 r r j u u
i 1/22
j
i 1/2j
i 1/2
i 1/ 22
j
i 1/2j
i 1/2 -1/2 i 1/2 i 1/2 ij
j
J
1/2
i 1/2
i 1/2 ij
j
J
-r r r rn
J.
j
j
J
Discrete Nodal Balance
Equation
i i2
r
S
2 r r r i 1/2 i 1/2 i 2 S S S i 1/2 i 1/2 i
i 1/2 i 1/2
i 1/2
i 1/2 i 1/2
r i i i i i i 1/2 i j j S j j S Q S S
i 1/2 1/2 -i 1/2 i 1/2 i i r 1/2 i 1/2 i r r Q(r)rdr 2 (r)rdr r r Σ 2 rdr rJ(r) dr d r r r 1 2Nodal Expansion Method (NEM)
In this lowest order form, NEM considers a
quadratic expansion of the transverse
averaged flux on each cell
The expansion coefficients are determined by
applying Fick’s law in combination with
continuity of normal current.
Polynomial Basis 1
1/2 i 1/2 -i l lP(r), r r r N 0 l a r
i i r -r where ξ=±1/2 when r=ri+1/2
1/2 ), ( P N 0 l al l
P0()=1
2 / 1 2 / 1 lξ
dξ
0
,
l
0
P
Polynomial Basis 2
1/2 1/2 -i i i 2 1/2 -i 2 1/2 i i r ) d ) r (r 2 ) 2 / 1 ( P a ) 2 / 1 ( P a ) 2 / 1 ( P a 1/2) ( P 2 0a 0 0 1 1 2 2 1/2 i
l l l ) 2 / 1 ( P a ) 2 / 1 ( P a ) 2 / 1 ( P a 1/2) ( P 2 0 a 0 0 1 1 2 2 1/2 i
l l l
1 P
4 1 ξ 3 ξ P2 2 Polynomial Basis 3
i i 1 a i i i i i i i 0 r r a i i i i i i i i i 2 r r 2 r r a i 2 i i i i i 2 i i i i i ξ ) / r ( 2 1 3 4 1 ) / r ( 8 1 ξ ) / r ( 2 1 3 4 1 ) / r ( 8 1 6 2 3 1/2 ), ( P N 0 l al l Fick’s Law 1
d
)
(
d
D
-)
J(
i i i 1/2 i i 1/2 i i i i i i 1/2 i ) / r ) / r D J i 1/2 i i 1/2 i i i i i i 1/2 i ) / r ) / r D JFick’s Law 2
i i i i i i 1/2 i i 2 i 2 i i i 1/2 i i i i i 1/2 i D 4 1 D 6 j D 48 r D 2 1 j 4 r 1 D 2 j i i i i i i 1/2 i i 2 i 2 i i i 1/2 i i i i i 1/2 i 4D D 6 j D 48 r D 2 1 j 4 r 1 D 2 j 2 i i i i D 48 D 16 1Equations per Node
i i 1/2 i i 1/2 i i 1/2 im
j
n
j
p
j
i i 1/2 i i 1/2 i i 1/2 it
j
o
j
p
j
1/2 i 1/2 i 1/2 i 1/2 i 1/2 i 1/2 i 1/2 i 1/2 i i i i r i S j S j S j S j S 1 Q 1Matrix Form
S
J
F
k
1
J
A
eff
J
unknown vector A 3Nx3N band matrix,where N is the total number of nodes
F
3Nx3N diagonal matrix (fission source term)only (3i-1)th elements contain nonzeroMatrix Equation 1
N N eff N N k F J 1 J A Nx3N 3 N N N a 1/2 N N a 1/2 -N N a 1/2 -N 4)) -(3x(3N N N 1 -N 1 -N a 1/2 -N 1 -N 3)) -N 3 ( 3) -N 3 (( 1 -N )) 3 ) 6 3 (( N 1 p 0 m S S 1 S S S S -0 0 p 1 o 0 0 n 0 0 S S 0 0 t A 0 A x x NMatrix Equation 2
1/2 3/2 3/2 N-1/2 N 1/2 T N j j j ... j j J Nx3N 3 (3x3) 1 ) 3 3 ( ) 3 3 ( ) 3 3 ( (3x3) 1 ) 3 3 ( ) 3 3 ( ) 3 3 ( (3x3) 1 N F ... 0 0 0 ... F 0 0 ... 0 F F x x x x x xIteration
J
is known from initial estimates
NewJ
vector is found with a linear system solver
New keff estimate is found after fission source iteration
Iteration continues until the difference between two successive keff estimates drops below the convergence criterion. N N eff N N k F J 1 J A One-group, Bare,
Homogeneous Reactor
D=0.65cm, a=0.12cm-1 and f=0.185cm-1. r D k 1 D r dr r d r dr d r 1 f eff a r B dr r d r dr d r 1 2One-Group Reflected Reactor
fuel refl.
R2=5cm
Fuel is the same material as previous
problem with same radius.
Reflector is a graphite material with
thickness 1.25cm.
Absorption cross-section and diffusion
coefficient of the graphite are taken to be 0.00032cm-1 and 0.84cm
Analytical Solution
B.C.
R1 R1
|
|
dr R d D dr R d D(1) 1 (2) 1 2 (2) R2 dr d 2 D R 4 1 )) R ( K ) R ( (-LI C ) R ( J C R 1 0 1 R 0 4 1 c 0 1 )) R ( K ) R ( I (-L D C ) R ( J D C - 1 cc 1 c 1 4 R R 1 R 1 R 1 R 1 )) R ( K ) R ( I (L D ) R ( K ) R ( LI -) R ( J D ) R ( J 1 R 1 R 1 R 1 R R 1 R 0 1 R 0 1 c 1 c c 1 c 0 k =0.768077605Two-group, Bare, Reactor
First, critical radius is calculated for zero incoming current boundary condition. Then, QFEMR and NEMR results are compared to see how close they can calculate keff to critical value. S
0 D S dr d r dr d r 1 1 R1 f2 f1
0 D -S dr d r dr d r 1 2 a2 2 S,1 Analytical Solution
R)
(B
J
D
2B
R)
(B
J
0 1
1 1 1 1R)
(B
J
D
2B
R)
(B
J
0 2
2 2 1 2 R=41.8931096cm S=0.116309825TRIGA
Fast and thermal cross-sections are obtained after
the ring homogenizations
NEMR finds the effective multiplication factor as
k
eff
By multiplying the number of annular regions in the
basic mesh by an integer (degree of refinement), finer meshes may be produced.
QFEMR with 320 quadratic elements or 16 degree of
refinement (finest mesh) gives keff=1.21051196.
% 00255016 . 0 21051196 . 1 % 100 | 21054283 . 1 21051196 . 1 | Error(%)
CONCLUSION
NEM and quadratic FEM were shown to be of better accuracy with respect to linear
FEM. It also appears that NEM is a practical method for the problems in which the mesh is very coarse (1, 2, 3 nodes etc.).